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The work function (phi) of some metals is listed below. The number of metals which will show photoelectric effect when light of 300nm wavelength falls on the metal. The Metal is |
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Answer» `= (hc)/(lambda)n impliesE = (6.6xx10^(-34) x 10^(8))/(300xx0^(-9))` `E` in eV `=(6.6xx10^(-34) xx 3 xx 10^8)/( 300xx10^(-9) xx 1.6xx 10^(-19)) = 4.16 eV` So , number of metals showing photo-electric effects will be (4) i.e., Li, Na , K , MG |
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