The work function (phi) of some metals is listed below. The number of metals which will show photoelectric effect when light of 300 nm wavelength falls on the metal is {:("Metal",Li,Na,K,Mg,Cu,Ag,Fe,Pt,W),(phi(eV),2.4,2.3,2.2,3.7,4.8,4.3,4.7,6.3,4.75):}

The work function (phi) of some metals is listed below. The number of

1.	The work function (phi) of some metals is listed below. The number of metals which will show photoelectric effect when light of 300 nm wavelength falls on the metal is {:("Metal",Li,Na,K,Mg,Cu,Ag,Fe,Pt,W),(phi(eV),2.4,2.3,2.2,3.7,4.8,4.3,4.7,6.3,4.75):}
Answer» Solution :Energy associated with the incident photon `= (hc)/(lamda)` i.e., `E = ((6.6 xx 10^(-34) Js) (3 xx 10^(8) ms^(-1)))/((300 xx 19^(-9) m))` `= 6.6 xx 10^(-19) J = (6.6 xx 10^(-19))/(1.6 xx 10^(-19)) EV = 4.12 eV` `:.` Metals showing photoelectric effect will be Li, Na, K and Mg only i.e., 4 metals, (which have WORK FUNCTION less than 4.12 eV)