The workdone in twisting a steel oflength0.25 meter and radius 1 mmthroughan angleof 45^(0) will be if eta=8xx10^(10) pascal

The workdone in twisting a steel oflength0.25 meter and radius 1 mmthr

1.	The workdone in twisting a steel oflength0.25 meter and radius 1 mmthroughan angleof 45^(0) will be if eta=8xx10^(10) pascal
Answer» 15 JOULE 0.15 joule 1.5 joule 0.015 Solution :`W=(1)/(2) (eta pi R^(4))/(2l)theta^(2)` `W=(8xx10^(10) xx 3.14 xx (10^(-3))^(4))/( 4xx0.25) xx ((3.14)/(4))^(2) =0.15` joule HENCETHE correct answer will be (2)