The worst case time complexity of insertion sort is O(n^2). What will be the worst case time complexity of insertion sort if the correct position for inserting element is calculated using binary search?(a) O(nlogn)(b) O(n^2)(c) O(n)(d) O(logn)The question was asked by my school principal while I was bunking the class.Question is taken from Insertion sort topic in portion Sorting of Data Structures & Algorithms II

The worst case time complexity of insertion sort is O(n^2). What will

1.	The worst case time complexity of insertion sort is O(n^2). What will be the worst case time complexity of insertion sort if the correct position for inserting element is calculated using binary search?(a) O(nlogn)(b) O(n^2)(c) O(n)(d) O(logn)The question was asked by my school principal while I was bunking the class.Question is taken from Insertion sort topic in portion Sorting of Data Structures & Algorithms II
Answer» CORRECT answer is (b) O(n^2) For explanation: The use of binary search reduces the TIME of finding the correct position from O(n) to O(LOGN). But the worst case of insertion sort REMAINS O(n^2) because of the series of swapping operations required for each insertion.

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