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The zero of the polynomial x2 ‒ √2x – 12 are |
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Answer» We have, f(x) = x2 ‒ √2x – 12 Now, put f(x) = 0 x2 ‒ √2x – 12 = 0 x2 - 3√2x + 2√2x - 12 = 0 x(x ‒ 3√2) + 2√2(x – 3√2)=0 (x ‒ 3√2) + (x + 2√2) = 0 Thus, x= 3√2 , -2√2 |
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