1.

The zeros of the polynomial x2-√2x -12 are(A) √2, -√2(B) 3√2, -2√2(C) -3√2, 2√2(D) 3√2, 2√2 

Answer»

Answer:(B) 3√2, -2√2

We have,
f(x) = x2-√2x -12
Now, put f(x) = 0
x2-√2x –12 = 0
x2 - 3√2x + 2√2x – 12 = 0
x(x - 3√2) + 2√2(x - 3√2) = 0
(x - 3√2)(x + 2√2) = 0
x - 3√2 = 0 or x + 2√2 = 0
x = 3√2 or x = -2√2
So, the zeros of given polynomial are 3√2 and -2√2.


Discussion

No Comment Found

Related InterviewSolutions