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The zinc/silver oxide cell is used in hearing aids and electric watches. The following reactions take place: `ZntoZn^(2+)+2e^(-),E^(@)=0.76V` `Ag_(2)O+H_(2)O+2e^(-)to2Ag+2OH^(-),E^(@)=0.344V` (a) What is oxidized and reduced? (b) Find `E^(@)` of the cell and `DeltaG` in joules.

Answer» (a) Zn is oxidized and `Ag_(2)O` is reduced (as `Ag^(+)` ions change into Ag)
(b) `E_(cell)^(@)=E_(Ag_(2)O//Ag)^(@)(Red)+E_(Zn//Zn^(2+))^(@)(Ox)=0.344+0.76=1.104V`
`DeltaG=-nFE_(cell)^(@)=-2xx96500xx1.104J=-2.13xx10^(5)J`.


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