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Theaverage velocity of an ideal gas molecule at 300 K is 2 m//s. The average velocity at 1200 Kwill be |
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Answer» Solution :(B) `v_(av)=sqrt((8RT)/(PIM))rArrv_(av)propsqrtT` `(2)/(V_(2))=sqrt((300)/(1200))=sqrt((1)/(4))=(1)/(2)rArrv_(2)=4 m//s` |
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