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Thedecompositionof N_(2) O_(5)is representedby theequation 2N_(2)O_(5(g)) to 4NO_(2(g))+ O_(2(g)) (a ) Howis therate offormationof NO_(2)relatedto the rate offormationof O_(2)? (b ) Howis therateof formationof O_(2) relatedto therate ofconsumption of N_(2)O_(s)? |
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Answer» Solution : Given : `2N_(2)O_(5(g)) to 4NO_(2(g)) + O_(2(g))` (a)Rateof formationof `O_(2)` at time`t= (d[O_(2)])/(DT)` Theyare relatedto eachotherthrough RATE of reaction `:. ` Rateof reaction`=(1)/(4) (d[NO_(2)])/(dt)= (d[O_(2)])/(dt)` ( b) Rate ofconsumptionof `N_(2) O_(5)` at time `t= - (d[N_(2)O_(5)])/(dt)` Rateof reaction `=- (1)/(2)(d[N_(2)O_(5)])/(dt) =(d[O_(2)])/(dt)` INGENERAL Rate ofreaction`= -(1)/(2) (d[N_(2)O_(5)])/(dt)= (1)/(4) (d[NO_(2)])/(dt)= (d[O_(2)])/(dt)` |
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