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Theefficiencyof aheatengineworkingbetweenthe freezingpointand boilingpointof wateris |
Answer» <html><body><p>`6.25%`<br/>`20%`<br/>`26.8%`<br/>`12.5%`<br/></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/freezing-999806" style="font-weight:bold;" target="_blank" title="Click to know more about FREEZING">FREEZING</a> point of water `T_(L) = 0^(@)<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>` = 273 K <br/> `:.` Efficiency, `<a href="https://interviewquestions.tuteehub.com/tag/eta-446786" style="font-weight:bold;" target="_blank" title="Click to know more about ETA">ETA</a> = <a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> - (T_(L))/(T_(H)) = 1- (273)/(373) = 0.2681 , eta = 26.8%`</body></html> | |