1.

Theefficiencyof aheatengineworkingbetweenthe freezingpointand boilingpointof wateris

Answer»

`6.25%`
`20%`
`26.8%`
`12.5%`

Solution :FREEZING point of water `T_(L) = 0^(@)C` = 273 K
`:.` Efficiency, `ETA = 1 - (T_(L))/(T_(H)) = 1- (273)/(373) = 0.2681 , eta = 26.8%`


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