1.

Thefreezing pointof anaqueoussolutionsis 272 .93 K . Calculatethemolalityof the solutionif molal depressionconstantforwateris 1.86 Kg mol^(-1)

Answer»


Solution :Given :Forpurewater `T_(o) = 273 K`
Forsolution`T_(R)= 273 .93 K`
`K_(r)= 1.86 K kg MOL^(-1)`
Molalityof the solution`= m= ?`
Depression in thefreezingpoint `= Delta T_(f)= T_(o)- T_(f)= 273- 272 .93= 0.07 K`
`Delta T_(f)= K_(f)xx M`
`:. m = (Delta T_(f))/(K_(f)) = (0.07)/(1.86)= 0.0376 "mol" kg ^(-1)`


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