Theionization constant of HF, HCOOH and HCN at 298 K are 6.8xx10^(-4), 1.8xx10^(-4)and 4.8xx106(-9) respectively. Calculate the ionization constant of the corresponding conjugate base.

Theionization constant of HF, HCOOH and HCN at 298 K are 6.8xx10^(-4),

1.	Theionization constant of HF, HCOOH and HCN at 298 K are 6.8xx10^(-4), 1.8xx10^(-4)and 4.8xx106(-9) respectively. Calculate the ionization constant of the corresponding conjugate base.
Answer» SOLUTION :For `F^(-) , " " K_(B) = K_(w)//K_(a) = 10^(-14)//(6.8xx10^(-4))=1.47 XX 10^(-11) ~= 1.5 xx 10^(-11)`. For `HCO O^(-) , " " K_(b) = 10^(-14)//(1.8xx10^(-4))=5.6xx10^(-11)` For `CN^(-), " " K_(b) = 10^(-14) // (4.8xx10^(-9))=2.08 xx 10^(-6)`