Saved Bookmarks
| 1. |
Then choose the correct option in which matching is correct |
|
Answer» Correct Answer - [(A)QR(B)RST(C)Q(D)PRST] (A) if torque zero about centre of circular motion then angular momentum will be constant (B) :. I omega = constant I decrease the omega increase (C) in pure Rolling work done by frictional force zero (D) An external force increases the speed of centre of mass |
|