then its area is(a) 24 35 cm (6) 12 35 cm2 (c) 6/35 cm2 (d) 150 cm13.

1.	then its area is(a) 24 35 cm (6) 12 35 cm2 (c) 6/35 cm2 (d) 150 cm13. The sides of a triangle are 35 cm, 54 cm and 61 cm. The length of its longest altitude is( d) 165 cm (b) 10 5 cm245 cm (d) 28 cm(NCERT Exemplar
Answer» In a triangle the shortest side acts as the base for the longest altitude. Here, in the given question the side of 35 cm length is the shortest. Hence it will act as the base for the longest altitude. Thee altitude divides its base into two parts.Let's assume the length of one part be x. Then the length of the second part will become (35 - x). Now by using Pythagoras theorem the length of the altitude is given by.L²= [54²-x²]........(i) and also byL²= [61²-(35-x)²]........(ii) By substracting eq(i) from eq (ii) we get61²-54²-(35-x)²+x²=070x =420x=6 Now substituting the value of x in eq (i) we getL² =54²-6²L=√2880L =24√5 (c) is correct option correct option

then its area is(a) 24 35 cm (6) 12 35 cm2 (c) 6/35 cm2 (d) 150 cm13. The sides of a triangle are 35 cm, 54 cm and 61 cm. The length of its longest altitude is( d) 165 cm (b) 10 5 cm245 cm (d) 28 cm(NCERT Exemplar

Answer»

In a triangle the shortest side acts as the base for the longest altitude.

Here, in the given question the side of 35 cm length is the shortest. Hence it will act as the base for the longest altitude.

Thee altitude divides its base into two parts.Let's assume the length of one part be x. Then the length of the second part will become (35 - x).

Now by using Pythagoras theorem the length of the altitude is given by.L²= [54²-x²]........(i) and also byL²= [61²-(35-x)²]........(ii)

By substracting eq(i) from eq (ii) we get61²-54²-(35-x)²+x²=070x =420x=6

Now substituting the value of x in eq (i) we getL² =54²-6²L=√2880L =24√5