Thenumber of atoms presents in 20 g of calciumwill equal to the number of atoms presents in (20 g Ca = (1)/(2) Ca) (Ca = (6.023 xx 10^(23))/(2) = 3.012 xx 10^(23))

Thenumber of atoms presents in 20 g of calciumwill equal to the number

1.	Thenumber of atoms presents in 20 g of calciumwill equal to the number of atoms presents in (20 g Ca = (1)/(2) Ca) (Ca = (6.023 xx 10^(23))/(2) = 3.012 xx 10^(23))
Answer» `12 G C` `12.15 g Mg` `24.0 g C` `24.3 gMg` Solution :`24.3 g Mg = 1 mol, so 12.15 g = (1)/(2) mol`