Theorem 10.1 : Equal che ds of a circle subtend equal angles at the ce

1.	Theorem 10.1 : Equal che ds of a circle subtend equal angles at the centre1. R
Answer» Given : In a circle C(O,r), chord AB = chord CD. To Prove :∠AOB =∠COD. Proof : In△AOB and△COD AO = CO [radii of same circle] BO = DO [radii of same circle] Chord AB = Chord CD [given] ⇒△AOB≅△COD [by SSS congruence axiom] ⇒∠AOB =∠COD. [c.p.c.t.]

Theorem 10.1 : Equal che ds of a circle subtend equal angles at the centre1. R

Answer»

Given : In a circle C(O,r), chord AB = chord CD.

To Prove :∠AOB =∠COD.

Proof : In△AOB and△COD

AO = CO [radii of same circle]

BO = DO [radii of same circle]

Chord AB = Chord CD [given]

⇒△AOB≅△COD [by SSS congruence axiom]

⇒∠AOB =∠COD. [c.p.c.t.]