1.

Ther rate of decomposition of a substance A becomes eight times when its concentration is doubled. What is the order of reaction?

Answer»


Solution :LET the equation for the reaction be rate (r ) = `k[A]^(n)`
When the concentration of A is DOUBLED, the rate equation may be EXPRESSED as:
rate (8r) = `(k[2A]^(n))`
`(8r)/(r ) = (k[2A])^(n)/(k[A]^(n)` or `8=(2)^(n)` or `(2)^(3)=(2)^(n), n=3` (THIRD ORDER reaction)


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