1.

Therate of areactionat 600 Kis 7.5 xx 10^(5)timesthe rate ofthe samereactionat 400 K. Calculatethe energyof activationfor the reaction.

Answer»


SOLUTION :Given : `(R_(2))/(R_(1)) = 7.5 xx 10^(5)`
Fromthe hint `,(R_(2))/(R_(1))= (K_(2))/(K_(1)) = 7.5 xx 10^(5)`
Initialtemperature= `T_(1)= 400 K` Finaltemperature = `T_(2) = 600 K`
ENERGYOF activation`=E_(a) = ?`
`log_(10).(k_(2))/(k_(1))= (E_(a) (T_(2)-T_(1)))/(2.303 R xx T_(1) xx T_(2))`
`= (2.303 xx 8.314 xx 400 xx 600)/((600 -400)) log_(10)7.5 xx 10^(5)`
`=(2.303 xx 8.314 xx 400 xx 600xx 5.875)/(200)`
`= 135000 J mol ^(-1)=135 kJ mol^(-1)`


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