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There are 10 points in a plane out of these points no three are in the same straight line except 4 points which are collinear. How many (i) straight lines (ii) trian-gles (iii) quadrilateral, by joining them? |
Answer» (i) Required number of straight lines `=.^(10)C_(2)-.^(4)C_(2)+1=(10*9)/(1*2)-(4*3)/(1*2)+1=45-6+1=40` (ii) Required number of triangles `=.^(10)C_(3)-.^(4)C_(3)=(10*9*8)/(1*2*3)-.^(4)C_(1)=120-4=116` (iii) Required number of quadrilaterals `=.^(10)C_(4)-(.^(4)C_(3).^(4)C_(1)+.^(4)C_(4).^(6)C_(0))` `=(10*9*8*7)/(1*2*3*4)-(.^(4)C_(1)*.^(6)C_(1)+1.1)` `=210-(4xx6+1)=210-25=185` |
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