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There are 15 APs whose common differences are 1, 2, 3,…..15 respectively, the first term of each being 1. Then sum of their 15th terms is (1) 1695 (2) 1792 (3) 1800 (4) 1924 |
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Answer» (1) 1695 15th term of these AP’s will form an AP in which first term = 15, common difference = 14 so, s15 = 15/2 [30 + 196] = 1695 |
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