1.

There are 20 units cubes all of whose faces are white, and 44 units cubes all of whose faces are red. They are put together to form a bigger cube (4 x 4 x 4). What is the minimum number of white visible on this larger cube?(a) 20(b) 14(c) 12(d) 8

Answer»

Answer is : (c) 12

Given, 4 x 4 x 4 cubes is made 64 faces 1 x 1 x 1 cubes.

Total cubes = 64, White = 20, Red = 44

To find minimum number of visible white box counting total visible faces of unit cube.

Total number of faces of small cube on bigger cube except boundary cubes = 4 x 6 = 24

Counting boundary cubes = 16+8+8 = 32

∴ Total visible faces = 56

But we have 44 red cube.

∴ Minimum number of white faces cubes which are visible = 56 - 44 = 12



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