

InterviewSolution
Saved Bookmarks
1. |
There are 20 units cubes all of whose faces are white, and 44 units cubes all of whose faces are red. They are put together to form a bigger cube (4 x 4 x 4). What is the minimum number of white visible on this larger cube?(a) 20(b) 14(c) 12(d) 8 |
Answer» Answer is : (c) 12 Given, 4 x 4 x 4 cubes is made 64 faces 1 x 1 x 1 cubes. Total cubes = 64, White = 20, Red = 44 To find minimum number of visible white box counting total visible faces of unit cube. Total number of faces of small cube on bigger cube except boundary cubes = 4 x 6 = 24 Counting boundary cubes = 16+8+8 = 32 ∴ Total visible faces = 56 But we have 44 red cube. ∴ Minimum number of white faces cubes which are visible = 56 - 44 = 12 |
|