There are 3 bags which are known to contain 2 white and 3 black, 4white and 1 black, and 3 white and 7 black ball, respectively. A ball isdrawn at random from one of the bags and found to the black ball. Then theprobability that it was drawn from the bag containing the most black ball is`7//15`b. `5//19`c. `3//4`d. none of theseA. `7//15`B. `5//19`C. `3//4`D. None of these

There are 3 bags which are known to contain 2 white and 3 black, 4whit

1.	There are 3 bags which are known to contain 2 white and 3 black, 4white and 1 black, and 3 white and 7 black ball, respectively. A ball isdrawn at random from one of the bags and found to the black ball. Then theprobability that it was drawn from the bag containing the most black ball is`7//15`b. `5//19`c. `3//4`d. none of theseA. `7//15`B. `5//19`C. `3//4`D. None of these
Answer» Correct Answer - A Consider the following events. A: ball drawn is black `E_(1):` bag I is chosen `E_(2):` bag II is chosen `E_(3):` bag III is chosen Then, `P(E_(1))=(E_(2))=P(E_(3))=1/3` `P(A//E_(1))=3/5,P(A//E_(2))=1/5,P(A//E_(3))=7/10` Therefore, the required probability is `P(E_(3)//A)=(P(E_(3))P(A//E_(3)))/(P(E_(1))P(A//E_(1))+P(E_(2))P(A//E_(2)))=7/15` `" "+P(E_(3))P(A//E_(3))`

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