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There are 5 members in Prajakta's family. Prajakta's husband is 5 years older than her and they have 2 sons and Prajakta's father in law is twice the age of her husband. The ratio between the present age of the elder son and the age of the younger son 1 year later is 2 ∶ 1 and the ratio between the present age of younger son and his father is 1 ∶ 5. What is the average age of the family if the ratio between the age of Prajakta two years later and his husband one year later is 8 ∶ 9?1. 35 years2. 28.5 years3. 36.5 years4. 31.6 years5. 25.75 years |
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Answer» Correct Answer - Option 4 : 31.6 years Let the present age of Prajakta be x Then, the present age of her husband = x + 5 Now, According to question The ratio between the age of Prajakta two year later and his husband one year later is 8 ∶ 9 ⇒ (x + 2)/(x + 6) = 8/9 ⇒ 9x + 18 = 8x + 48 ⇒ x = 30 ∴ Present age of Prajakta = 30 yrs Present age of Prajakta's husband = 35 yrs The ratio between the present age of younger son and his father is 1 ∶ 5 Let the age of the younger son and his father be x and 5x respectively ⇒ 5x = 35 ⇒ x = 7 ∴ Present age of younger son = 7 yrs Now, the ratio between the present age of the elder son and the age of the younger son 1 year later is 2 ∶ 1 ⇒ S/8 = 2/1 ⇒ S = 16 S → Present age of elder son ∴ Present age of elder son = 16 yrs Age of Prajakta's father in law = 2 × 35 = 70 yrs ∴ Average age of the family = (30 + 35 + 7 + 16 + 70)/5 = 31.6 yrs |
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