There are 6 items in column A and 6 items in column B. A student is as

1.	There are 6 items in column A and 6 items in column B. A student is asked to match each item in column A with an item in column B. How many possible, correct or incorrect answers are there to this question?
Answer» To find: number of possibilities of a selection of answers. Each item in column A can select another item in column B. Therefore the question involves selecting each item from column A to each item in column B. this can be done in P(6,6) Formula: Number of permutations of n distinct objects among r different places, where repetition is not allowed, is P(n,r) = n!/(n-r)! Therefore, a permutation of 6 different objects in 6 places is P(6,6) = \(\frac{6!}{(6-6)!}\) = \(\frac{6!}{0!}\) = \(\frac{720}{1}\) = 720. Therefore, the possible number of selecting an incorrect or correct answer is 720.

There are 6 items in column A and 6 items in column B. A student is asked to match each item in column A with an item in column B. How many possible, correct or incorrect answers are there to this question?

Answer»

To find: number of possibilities of a selection of answers.

Each item in column A can select another item in column B.

Therefore the question involves selecting each item from column A to each item in column B. this can be done in P(6,6)

Formula:

Number of permutations of n distinct objects among r different places, where repetition is not allowed, is

P(n,r) = n!/(n-r)!

Therefore, a permutation of 6 different objects in 6 places is

P(6,6) = \(\frac{6!}{(6-6)!}\)

= \(\frac{6!}{0!}\) = \(\frac{720}{1}\)

= 720.

Therefore, the possible number of selecting an incorrect or correct answer is 720.