There are five species P, Q, R, S and T. Spectroscopical analysis shows that P,Qand R arehomonuclear diatomic species and have their bond order 2.4, 1.5 and 2.5 respectively and rest two species S and T are heteronuclear diatomic species and have bond order 3 and 2 respectively. All homonuclear diatomic species are paramagnetic and all heteronuclear species are diamagnetic in nature. P, R , S and T are monocovalent positive ion and Q is monovalent negative ion: Q. The incorrect statements is :

There are five species P, Q, R, S and T. Spectroscopical analysis show

1.	There are five species P, Q, R, S and T. Spectroscopical analysis shows that P,Qand R arehomonuclear diatomic species and have their bond order 2.4, 1.5 and 2.5 respectively and rest two species S and T are heteronuclear diatomic species and have bond order 3 and 2 respectively. All homonuclear diatomic species are paramagnetic and all heteronuclear species are diamagnetic in nature. P, R , S and T are monocovalent positive ion and Q is monovalent negative ion: Q. The incorrect statements is :
Answer» If R has 15 electrons then bond order of R is GREATER than its parent molecule If Q has 17 electrons then bond order of Q is less than its parent molecule If P has 17 electrons then bond order of P is greater than its parent molecule On addition of TWO electrons inP(having 13 electrons) the bond order remains same Answer :C