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There are n black balls and 2 red balls in a bag. One by one balls are drawn from the bag X wins as soon as 2 black balls are drawn and Y wins as soon as 2 red balls are drawn. The game continuous until one of 2 wins. Let X(n) and Y(n) denotes the probability that X and Y wins respectively. The value of lim_(n+prop) (X(2).X(3).X(4)...(n)) is |
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Answer» `1//3` |
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