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There are N molecules of a gas in a containter. If this number is increased to 2N, what will be (i) pressure (ii) total energy (iii) rms speed of the gas ? |
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Answer» (i) As `P=1/3 M/V c^(2) = 1/3 (mN)/(V) C^(2)`, therefore, when N is doubled, P becomes twice. (ii) As `E=3/2 P`, therefore, when P is doubled, total energy E is also doubled. (iii) rms speed remains the same as it depends only on temperature. |
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