There are three numbers. The first number is `33^(1/3)%` more than the second number and `50%` more than the third number. What percentage of the third number is the second number ?A. `107.5%`B. `112.5%C. `117.5%`D. `112.5%`

There are three numbers. The first number is `33^(1/3)%` more than the

1.	There are three numbers. The first number is `33^(1/3)%` more than the second number and `50%` more than the third number. What percentage of the third number is the second number ?A. `107.5%`B. `112.5%C. `117.5%`D. `112.5%`
Answer» Correct Answer - B Let the first number, the second number and the third number be f, s and t respectively. `f=s+(33(1)/(3))/(100)s=4/3` `f=t+50/100t=3/2t` `f=4/3s=3/2t` `impliess9/8t=9/8(100)%of t` i.e., `112.5%` of t

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There are three numbers. The first number is `33^(1/3)%` more than the second number and `50%` more than the third number. What percentage of the third number is the second number ?A. `107.5%`B. `112.5%C. `117.5%`D. `112.5%`

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