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There are two electric bulb : (i) marked `60 W, 220 V` and (ii) marked `100W, 220 V` Which one of them has higher resistance ? |
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Answer» (i) `R_1 = (V^2)/(P_1) = ((220)^2)/(100) Omega = 484 Omega`, (ii) `R_2 = (V^2)/(P_2) = ((220)^2)/(60) Omega = 806.7 Omega` Clearly, `R_2` (resistance of 60 W bulb) is higher. |
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