There are two identical small holes, each of area of cross-sections on the opposite sides of a tank containing a liquid of density rho. The difference in height between the holes is 'h'. Tunk is resting on a smooth horizontal surface. Find the horizontal force which will have to be applied on the tank to keep it in equilibrium.

There are two identical small holes, each of area of cross-sections on

1.	There are two identical small holes, each of area of cross-sections on the opposite sides of a tank containing a liquid of density rho. The difference in height between the holes is 'h'. Tunk is resting on a smooth horizontal surface. Find the horizontal force which will have to be applied on the tank to keep it in equilibrium.
Answer» SOLUTION :`F=F_(1)-F_(2)=rhoav_(1)^(2)-rhoav_(2)^(2)` `rhoa(2gh_(1))-rhoa(2gh_(2))=2rhoag(h_(1)-h_(2))=2rhogh`