There are two pendulums of length l_(1) and l_(2) start vibrating. At some instant, the two are in mean position in the same phase. Calculate after how many vibrations of shorter pendulum, the two wll be in phase in the mean position? [(l_(1)gtl_(2)),l_(1)=121cm, l_(2)=100cm]

There are two pendulums of length l_(1) and l_(2) start vibrating. At

1.	There are two pendulums of length l_(1) and l_(2) start vibrating. At some instant, the two are in mean position in the same phase. Calculate after how many vibrations of shorter pendulum, the two wll be in phase in the mean position? [(l_(1)gtl_(2)),l_(1)=121cm, l_(2)=100cm]
Answer» 11 10 9 8 Solution :`T_(1)=2pisqrt(((l_(1))/(g))),T_(2)=2pisqrt(((l_(2))/(g)))(l_(1)gtl_(2))` Let SHORTER PENDULUM makes n vibrations, then the longer will make one less than n to COME in phase again. `nT_(1)=(n-1)T_(1)` `2pisqrt(((l_(2))/(g))n)=(n-1)2pisqrt(((l_(1))/(g)))` `THEREFORE"n=11"`