There are two positive integers X & Y. When X is divided by 237, the remainder is 192. When Y is divided by 117 the quotient is the same but the remainder is 108. Find the remainder when the sum of X & Y is divided by 118.

There are two positive integers X & Y. When X is divided by 237, the r

1.	There are two positive integers X & Y. When X is divided by 237, the remainder is 192. When Y is divided by 117 the quotient is the same but the remainder is 108. Find the remainder when the sum of X & Y is divided by 118.
Answer» There are two positive integers $X$ & $Y .$ When $X$ is divided by $237,$ the remainder is $192.$ When Y is divided by $117$ the quotient is the same but the remainder is $108.$ Find the remainder when the sum of $X$ & $Y$ is divided by $118.$

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There are two positive integers X &amp; Y. When X is divided by 237, the remainder is 192. When Y is divided by 117 the quotient is the same but the remainder is 108. Find the remainder when the sum of X &amp; Y is divided by 118.

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There are two positive integers X & Y. When X is divided by 237, the remainder is 192. When Y is divided by 117 the quotient is the same but the remainder is 108. Find the remainder when the sum of X & Y is divided by 118.