1.

There are two sets A and B each of which consists of three numbers in A.P.whose sum is 15 andwhere D and d are the common differences such that D-d=1. If p/q=7/8, where p and q are the product of the numbers ,respectively, andd gt 0 in the two sets . The sum of the products of the numbers is set A taken two at at time is

Answer»

51
71
74
86

Solution :Let NUMBERS in set A be a-D,a,a+D and those in set B be b-d,b,b+d. Now,
3a=3b=15
or a=b=5
Set A = {5-D,5,5+D}
set B = {5-d,5,5+d}
where D=d+1
ALSO,
`p/q=(5(25-D^(2)))/(5(25-d^(2)))=7/8`
`rArr25(8-7)=8(d+1)^(2)-7d^(2)`
`rArrd=-17,1` but `dgt0rArrd=1`
So, the numbers in set A are 3,5,7 and the nnumbers in set are 4,5,6.
Now, sum of PRODUCT of numbers in set are 4,5,6.
Now, sum of product of numbers in set A taken two at a TIME is `3xx5+3xx7+5xx7=71`. The sum of product ofnumbers in set B taken two at a time is `4xx5+5xx6+6xx4=74`.
Also,
`p=3xx5xx7=105 and q=4xx5xx6=120`
`rArrq-p=15`


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