There is 1 mol liquid (molar volume 100 ml) in an adiabatic container initial, pressure being 1 bar. Now the pressure is steeply increased to 100 bar ,and the volume decreased by 1 mL under constant pressure of 100 bar. Calculate DeltaH "and" DeltaE. [Given 1 bar = 10^(5) N//m^(2)]

There is 1 mol liquid (molar volume 100 ml) in an adiabatic container

1.	There is 1 mol liquid (molar volume 100 ml) in an adiabatic container initial, pressure being 1 bar. Now the pressure is steeply increased to 100 bar ,and the volume decreased by 1 mL under constant pressure of 100 bar. Calculate DeltaH "and" DeltaE. [Given 1 bar = 10^(5) N//m^(2)]
Answer» `DeltaE=0 J, DeltaHne0 J` `DeltaH=990 J, DeltaE=10 J` `DeltaE=20 J, DeltaH=890 J` `DeltaE=0 J, DeltaH=10 J` ANSWER :B