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There is a digit at the 10th place of 6n, in which n is a natural number that is greater than 1, it can be:1. 1, 2, 3, 4, 52. 1, 3, 5, 7, 93. 1, 2, 6, 8, 94. 1, 3, 5, 8, 9 |
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Answer» Correct Answer - Option 1 : 1, 2, 3, 4, 5 Given: There is a digit at the 10th place of 6n. Where n is a natural number that is greater than 1. Calculation: Let be n= 2, ,3, 4, 5,... ⇒ 6 × 2 = 12 = 1 ⇒ 6 × 3 = 18 = 1 ⇒ 6 × 4 = 24 = 2 ⇒ 6 × 5 = 30 = 3 ⇒ 6 × 6 = 36 = 3 ⇒ 6 × 7 = 42 = 4 ⇒ 6 × 8 = 48 = 4 ⇒ 6 × 9 = 54 = 5 ∴ It can be 1, 2, 3, 4, 5. |
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