1.

There is a hole at the bottom of a large open vessel. If water is filled upto a height h, it flows out in time t. if water is filled to a height 4h, it will flow out in timeA. `4t`B. `(t)/(4)`C. `(t)/(2)`D. `2t`

Answer» `t=sqrt((2)/(g))(A)/(a)(sqrt(H))implies(t_(1))/(t_(2))=(sqrt(H_(1)))/(sqrt(H_(2)))`


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