There is a ring or mass m and radius R is pivoted at a point O on its periphery. It is free to rotate about an axis perpendicular to its plane. What is the period of ring?

There is a ring or mass m and radius R is pivoted at a point O on its

1.	There is a ring or mass m and radius R is pivoted at a point O on its periphery. It is free to rotate about an axis perpendicular to its plane. What is the period of ring?
Answer» `T=2pi(((R)/(g)))` `T=2pisqrt(((2R)/(g)))` `T=pisqrt(((2R)/(g)))` `T=2pisqrt(((3R)/(g)))` Solution :d= R and l = `2mR^(2)` `because""T=2pisqrt([(l)/(MGD)])T=2pisqrt([(2mR^(2))/(MGR)])` `rArr""T=2pisqrt([(2R)/(g)])`