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There is a salt of weak acid and weak base the K_(a) of the acid is greater than the K_(b) of the base hence |
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Answer» Degree of HYDROLYSIS is independent of the concentration of the salt solution `K_(h) = (K_(w))/(K_(a)K_(b)) = ([HA][BOH])/([A^(-)][B^(+)]` and `h = sqrt((K_(w))/(K_(a)K_(b)))` Hence degree of hydrolysis is independent of the concentration of the salt taken. `{:("Further",A^(-)+H_(2)O hArr HA+OH^(-),,....(i)),(,B^(+)+H_(2)O hArr BOH + H^(+),,...(II)):}` Since `K_(a)` of HA is more than `K_(b)` of BOH so the extent of backward reaction in (i) is greater than the extent of of hydrolysis of `B^(+)` Hence choices (a), (c) and (d) are correct while (b) is incorrect. |
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