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There is a series `LCR` curcuit (as shown). An alternating source of emf having voltage `V=V_(0) sin omega t` is applied between `M` & `N`. Here `V_(M)-V_(N)=V_(0) sin omega t and 1/(omegaC)-omegaL=R` Potential difference across inductor i.e. `V_(Q)-V_(N)` isA. `V_(0)/(sqrt(2)R) omegaL sin (omegat+(3pi)/4)`B. `(V_(0)omegaL)/(sqrt(2)R) sin omegat`C. `(V_(0)omegaL)/(sqrt(2)R) sin (omegat+pi/2)`D. `(V_(0)omegaL)/(sqrt(2)R) cos omegat`

Answer» Correct Answer - A


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