InterviewSolution
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InterviewSolution
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There is a spring with netural length `L_(0)`. Two masses `m_(1)` and `m_(2)` are connected to both of its ends as shown in figure. The whole system is held at rest. At any time `t =0, m_(2)` is released and system starts free fall. Initial stretched length of spring before fall is `L.` what is the displacement of centre of mass as function of time? A. `g t^(2)`B. `(1)/(2)g t^(2)`C. `(g)/(K)t^(2)`D. `(m_(1)+m_(2))/(m_(1)m_(2))xxt` |
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Answer» Correct Answer - B `a_(cm) = (m_(1)a_(1)+m_(2)a_(2))/(m_(1)+m_(2)), a_(1) =a_(2) = g` `:. S = (1)/(2) a_(cm)t^(2) = (1)/(2)g t^(2)` |
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