There is blue colour formation if:A. Cu electrode is placed inside `AgNO_(3)` solutionB. Cu electrode is placed inside `ZnSO_(4)` solutionC. Cu electrode is placed inside dil `HNO_(3)`D. Cu electrode is placed inside dil `H_(2)SO_(4)`

There is blue colour formation if:A. Cu electrode is placed inside `Ag

1.	There is blue colour formation if:A. Cu electrode is placed inside `AgNO_(3)` solutionB. Cu electrode is placed inside `ZnSO_(4)` solutionC. Cu electrode is placed inside dil `HNO_(3)`D. Cu electrode is placed inside dil `H_(2)SO_(4)`
Answer» Correct Answer - A::C

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Based on the data given below, the correct order of reducing power is: `Fe_((aq.))^(3+) + e rarr Fe_((aq.))^(2+), E^(@) = +0.77 V` `Al_((aq.))^(3+) + 3e rarr Al_((s)), E^(@) = -1.66 V` `Br_(2(aq.)) + 2e rarr 2Br_((aq.))^(-), E^(@) = +1.08 V`A. `Br^(-) lt Fe^(2+) lt A1`B. `Fe^(2+) lt Al lt Br^(-)`C. `Al^(-) lt Br^(-) lt Fe^(2+)`D. `Al^(-) lt Fe^(2+) lt Br^(-)`
Based on the data given below, the correcy order of reducing power is: `Fe_((aq.))^(3+) + e rarr Fe_((aq.))^(2+), E^(@) = +0.77 V` `Al_((aq.))^(3+) + 3e rarr Al_((s)), E^(@) = -1.66 V` `Br_(2(aq.)) + 2e rarr 2Br_((aq.))^(-), E^(@) = +1.08 V`A. `Br^(-) lt Fe^(2+) lt Al`B. `Fe^(2+) lt Al lt Br^(-)`C. `Al lt Br^(-) lt Fe^(2+)`D. `Al lt Fe^(2+) lt Br^(-)`
Based on the data given below, the correcy order of reducing power is: `Fe_((aq.))^(3+) + e rarr Fe_((aq.))^(2+), E^(@) = +0.77 V` `Al_((aq.))^(3+) + 3e rarr Al_((s)), E^(@) = -1.66 V` `Br_(2(aq.)) + 2e rarr 2Br_((aq.))^(-), E^(@) = +1.08 V`A. `Br^(-) lt Fe^(2+) lt Al`B. `Fe^(2+) lt Al lt Br^-`C. `Al lt Br^(-) lt Fe^(2+)`D. `Al lt Fe^(2+) lt Br^(-)`
What are elementary reactions ?

There is blue colour formation if:A. Cu electrode is placed inside `AgNO_(3)` solutionB. Cu electrode is placed inside `ZnSO_(4)` solutionC. Cu electrode is placed inside dil `HNO_(3)`D. Cu electrode is placed inside dil `H_(2)SO_(4)`

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