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There is infinitely long straight thread carrying a charge with linear density `lambda`.Calculate the potential difference `A` and `B`. |
Answer» The electric field at perpendicular `x` from wire `vec(E ) = (lambda)/(2 pi in_(0) x) hat(i) , dx hat(i) + dyhat(j) + dz hat(k)` `vec(E ). d vec(r ) = (lambda)/(2 pi in_(0) x) dx` `V_(A) - V_(B) = - int_(eta d)^(d) vec(E) . dvec(r ) = -int_(eta d)^(d) |log_(e ) x|_(eta d)^(d)` ` = - (lambda)/(2 pi in_(0)) log_(e ) ((1)/(eta))` `= (lambda)/(2 pi in_(0)) log_(e ) (eta)` |
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