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There is same change in length when a 33000 N tensile force is applied on a steel rod of area of cross-section `10^(-3)m^(2)` . The change of temperature reuired to produce the same elongation, if the steel rod is heated , if (The modulus of elasticitay is ` 3xx10^(11) N//m^(2)` and the coefficient of linear expansion of steel is ` 11 xx 10^(-5) //^(@)C`).A. `20^(@)`CB. `15^(@)C`C. `10^(@)C`D. `0^(@)C` |
Answer» Correct Answer - C (c) Modulus of elasticity `=("Froce")/("Area")xx(l)/(Deltal)` `3xx10^(11)=(3000)/(10^(-3))xx(l)/(Deltal)` `(Deltal)/(l)=(33000)/(10^(-3))xx(1)/(3xx10^(11))=11xx10^(-5)` Change in length, `(Deltal)/(l)=alpha DeltaT` `11xx10^(-5)=1.1xx10^(-5)xxDeltaT` `implies DeltaT=10K` or `10^(@)C` |
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