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Thermal decomposition of a compound is of first order. If 50% of a sample of the compound is decomposed in 120 minutes how long will it take for 90% of the compound to decompose? |
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Answer» `399` min `K = (0.693)/(T_(1//2)) = (0.693)/(120) = 5.77 XX 10^(3) min-1` Now we know that for a first order reaction `K = (2.303)/(t) "log"((a)/(a-x))` Here the initial CONCENTRATIION `a = 100` and `N = 90` `:. 5.77 xx 10^(-3) = (2.303)/(t) "log"(100)/(100-90)` `t = (2.303)/(5.77 xx 10^(-3))"log"((a)/(a-x))` Solving,`t = 399` minute |
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