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InterviewSolution
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These resistors of `10Omega,15Omega and 5Omega` are connected in parallel. Find their equivalent resistance. |
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Answer» `R_(1)=10Omega " "R_(2)=15Omega" "R_(3)=5Omega` `R_(1), R_(2) and R_(3)` are connected in parallel then equivalent resistance ® is given by `(1)/(R)=(1)/(R_(1))+(1)/(R_(2))+(1)/(R_(3))` `(1)/(R)=(1)/(10)+(1)/(15)+(1)/(5)=(3+2+6)/(30)=(11)/(30)` `therefore` Equivalent resistance , `R=(30)/(11)=2.72Omega` |
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