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Theshortestdistancetravelledby aparticleexecutingSHMform meanpositionin2 seconds isequalto( sqrt(3))/(2 ) timesof itsamplitude. Determineitstimeperiod . |
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Answer» Solution :GIVENDATA: `t=2 s,y= ( sqrt(3))/(2)A , T= ?` DISPLACEMENT` y=Asinomega t = ASIN( 2pi )/( T ) t` ` ( sqrt(3))/(2)A = Asin"" ( 2pi xx 2 ) /( t), SIN "" ( 4pi ) /( T)= ( sqrt(3))/(T ) = ( sqrt(3))/(2 ) = sin "" (pi )/(3)` ` therefore( 4pi )/(T )= (pi )/(3 ), T= 12 s` |
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