Thesolubility of AgCl (s) with solubility product 1.6xx10^(-10) in 0.1 MNaCl solution would be

Thesolubility of AgCl (s) with solubility product 1.6xx10^(-10) in 0.1

1.	Thesolubility of AgCl (s) with solubility product 1.6xx10^(-10) in 0.1 MNaCl solution would be
Answer» `1.26xx10^(-5) M` `1.6xx10^(-9) M` `1.6xx10^(-11)M` zero Solution :`{:(AgCl(s),OVERSET(+aq)hArr ,AG^(+)(aq),+,CL^(-)(aq)),(S,,S,,S+0.M"(from NaCl)"),(,,,,~=0.1M (" as " S lt lt 0.1)):}` `K_(sp)=[Ag^(+)][Cl^(-)]` `1.6xx10^(-10)=S(0.1) "or" S=1.6xx10^(-9)M`