theta=theta_0+omega_0t+1/2propt^2 from the first principles of differe

1.	theta=theta_0+omega_0t+1/2propt^2 from the first principles of differentiation.
Answer» Solution :CONSIDER the DEFINITION for angular speed, i.e `omega=(dtheta)/(DT)` i.e `dtheta=omegadt` i.e `dtheta=(omega_0+propt)dt` i.e `intdtheta=intomegadt+inttdt` i.e `theta=omega_0t+prop.(t^2)/(2)+C` Where 'C' is a constant. When `t=0,theta=theta_0,C=theta_0` HENCE `theta=theta_0+omega_0+1/2propt^2`

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