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Thetemperaturecoefficientof a reaction in 2 and the rateof thereaction at 25^(@)C is3 mol L^(-1) min^(-1) Calculate the rate at 75^(@)C. |
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Answer» Solution :According of Arrhenius, for every `10^(@)C` rise in the temperature, the rate of reaction is DOUBLED. Rise in the temperature `=75^(@)C-25^(@)C=50^(@)C` `=5XX10^(@)C` The increase in the rate of the reaction `=2^(5)=2` times The rate of reaction `75^(@)C=3xx32` `=96"MOL"L^(-1)"MIN"^(-1)`. |
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