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ThethresholdfrequencyV_(0)for ametalis7.0 xx 10^(14) s^(-1)Calculationthe kineticenergyofandelectron emittedwhenradiationoffrequencyv=1.0 xx 10^(15) s^(-1)hitsthe metal . |
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Answer» Solution :Accordingto Einsteinequation Kinetic energy`=(1)/(2) m_(e ) v^(2)` where`v_(0)= 7.0xx10^(14)s^(-1)` `=(6.626 xx 10^(34) j s ) ( 1.0 xx 10^(15) -7.0xx 10^(14)) s^(-1)` `=6.626 xx 10^(34)(10 xx 10^(14)-7.0xx 10^(14))` `19.878xx 10^(-20)` `=1.9879 xx 10^(19)J` |
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