1.

ThethresholdfrequencyV_(0)for ametalis7.0 xx 10^(14) s^(-1)Calculationthe kineticenergyofandelectron emittedwhenradiationoffrequencyv=1.0 xx 10^(15) s^(-1)hitsthe metal .

Answer»

Solution :Accordingto Einsteinequation
Kinetic energy`=(1)/(2) m_(e ) v^(2)`
where`v_(0)= 7.0xx10^(14)s^(-1)`
`=(6.626 xx 10^(34) j s ) ( 1.0 xx 10^(15) -7.0xx 10^(14)) s^(-1)`
`=6.626 xx 10^(34)(10 xx 10^(14)-7.0xx 10^(14))`
`19.878xx 10^(-20)`
`=1.9879 xx 10^(19)J`


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